How do you simplify sqrtx^(2n)* sqrty^(2n +1)? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer LM Oct 18, 2017 x^n * y^(n+0.5) Explanation: laws of indices: rootna = a^(1/n) (a^m)^n = a^(mn) a^m * a^n = a^(m+n) and in practice: sqrt(x) = x^(1/2) sqrt(x) ^(2n) = (x^(1/2))^(2n) (x^(1/2))^(2n) = x^(1n) = x^n sqrt(y) ^(2n+1) = (y^(1/2))^(2n+1) (y^(1/2))^(2n+1) = y^(n+0.5) y^(n+0.5) = y^n * y^0.5 = sqrty *y^n sqrtx^(2n)⋅sqrty^(2n+1) = x^n * sqrty *y^n x^n * y^(n+0.5) Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))? See all questions in Multiplication and Division of Radicals Impact of this question 1139 views around the world You can reuse this answer Creative Commons License