How do you simplify $(\sqrt{c} + d) (3 + \sqrt{5})$ $(sqrtc + d)(3 +sqrt5)$ ?

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How do you simplify $(\sqrt{c} + d) (3 + \sqrt{5})$ $(sqrtc + d)(3 +sqrt5)$ ?

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Answer 1 · 2017-04-08T04:19:57

$(\sqrt{c} + d) (3 + \sqrt{5}) = 3 \sqrt{c} + \sqrt{5} \sqrt{c} + 3 d + d \sqrt{5}$ $(sqrtc+d)(3+sqrt5)=color(blue)(3sqrtc+sqrt5sqrtc+3d+dsqrt5$

Explanation:

Simplify:

$(\sqrt{c} + d) (3 + \sqrt{5})$ $(sqrtc+d)(3+sqrt5)$

Use the FOIL method, which gives the order in which the terms of two binomials are multiplied: First, Outer, Inner, Last

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$(\sqrt{c} + d) (3 + \sqrt{5}) = (\sqrt{c} \cdot 3) + (\sqrt{c} \cdot \sqrt{5}) + (d \cdot 3) + (d \cdot \sqrt{5})$ $(sqrtc+d)(3+sqrt5)=(sqrtc*3)+(sqrtc*sqrt5)+(d*3)+(d*sqrt5)$

$(\sqrt{c} + d) (3 + \sqrt{5}) = 3 \sqrt{c} + \sqrt{5} \sqrt{c} + 3 d + d \sqrt{5}$ $(sqrtc+d)(3+sqrt5)=3sqrtc+sqrt5sqrtc+3d+dsqrt5$

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How do you simplify $(\sqrt{c} + d) (3 + \sqrt{5})$ $(sqrtc + d)(3 +sqrt5)$ ?

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How do you simplify (√c+d)(3+√5)(sqrtc + d)(3 +sqrt5)?

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How do you simplify $(\sqrt{c} + d) (3 + \sqrt{5})$ $(sqrtc + d)(3 +sqrt5)$ ?