How do you simplify $(\sqrt{a} - 4) (\sqrt{a} + 4)$ $(sqrta-4)(sqrta+4)$ ?

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How do you simplify $(\sqrt{a} - 4) (\sqrt{a} + 4)$ $(sqrta-4)(sqrta+4)$ ?

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Answer 1 · 2017-01-20T12:39:45

$a - 16$ $a-16$

Explanation:

$(\sqrt{a} - 4) (\sqrt{a} + 4)$ $(sqrta-4)(sqrta+4)$

Let's do each multiplication then add up the results:

$\sqrt{a} \sqrt{a} = a$ $sqrtasqrta=a$
$\sqrt{a} (4) = 4 \sqrt{a}$ $sqrta(4)=4sqrta$
$(- 4) \sqrt{a} = - 4 \sqrt{a}$ $(-4)sqrta=-4sqrta$
$(- 4) (4) = - 16$ $(-4)(4)=-16$

$a + 4 \sqrt{a} - 4 \sqrt{a} - 16 = a - 16$ $a+4sqrta-4sqrta-16=a-16$

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How do you simplify $(\sqrt{a} - 4) (\sqrt{a} + 4)$ $(sqrta-4)(sqrta+4)$ ?

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How do you simplify $(\sqrt{a} - 4) (\sqrt{a} + 4)$ $(sqrta-4)(sqrta+4)$ ?