How do you simplify #sqrt96divsqrt8#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Jun 15, 2015 # =color(red)( (2sqrt6)/sqrt2# Explanation: #sqrt96/sqrt8# #sqrt 96 = 4sqrt6# # sqrt8 = 2sqrt2# rewriting the expression: #(4sqrt6) / (2sqrt2)# # =color(red)( (2sqrt6)/sqrt2# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 980 views around the world You can reuse this answer Creative Commons License