How do you simplify $\frac{\sqrt{8}}{\sqrt{24}}$ $sqrt8/ sqrt24$ ?

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How do you simplify $\frac{\sqrt{8}}{\sqrt{24}}$ $sqrt8/ sqrt24$ ?

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Answer 1 · 2015-03-22T18:06:41

Take a one big root as :
$\sqrt{\frac{8}{24}} =$ $sqrt(8/24)=$ and simplyfy getting:
$= \sqrt{\frac{1}{3}} = \frac{\sqrt{1}}{\sqrt{3}} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} =$ $=sqrt(1/3)=(sqrt(1))/(sqrt3)=1/sqrt(3)=1/sqrt(3)*sqrt(3)/sqrt(3)=$
The last operation is called rationalization and it is used to avoid roots in the denominator:
$= \frac{\sqrt{3}}{3}$ $=sqrt(3)/3$

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How do you simplify $\frac{\sqrt{8}}{\sqrt{24}}$ $sqrt8/ sqrt24$ ?

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