How do you simplify $\sqrt{72} - \sqrt{50}$ $sqrt72-sqrt50$ ?

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Answer 1 · 2015-11-06T02:46:07

$\sqrt{72} - \sqrt{50} = \sqrt{2}$ $sqrt 72-sqrt 50=sqrt 2$

$\sqrt{72} - \sqrt{50}$ $sqrt 72-sqrt 50$

Write the prime factors for $72$ $72$ .

$\sqrt{2 \times 2 \times 2 \times 3 \times 3} - \sqrt{50}$ $sqrt(2xx2xx2xx3xx3)-sqrt 50$

Group like terms in pairs.

$\sqrt{(2 \times 2) \times 2 \times (3 \times 3)} - \sqrt{50}$ $sqrt((2xx2)xx2xx(3xx3))-sqrt 50$

Simplify.

$\sqrt{2^{2} \times 2 \times 3^{2}} - \sqrt{50}$ $sqrt(2^2xx2xx3^2)-sqrt 50$

Apply square root rule $\sqrt{a^{2}} = a$ $sqrt(a^2)=a$

$2 \times 3 \sqrt{2} - \sqrt{50}$ $2xx3sqrt2-sqrt50$

$6 \sqrt{2} - \sqrt{50}$ $6sqrt 2-sqrt 50$

Write the prime factors for $50$ $50$ .

$6 \sqrt{2} - \sqrt{2 \times 5 \times 5}$ $6sqrt 2-sqrt(2xx5xx5)$

Group like terms in pairs.

$6 \sqrt{2} - \sqrt{2 \times (5 \times 5)}$ $6sqrt 2-sqrt(2xx(5xx5))$

Simplify.

$6 \sqrt{2} - \sqrt{2 \times 5^{2}}$ $6sqrt 2-sqrt(2xx5^2)$

Apply square root rule $\sqrt{a^{2}} = a$ $sqrt(a^2)=a$

$6 \sqrt{2} - 5 \sqrt{2} =$ $6sqrt 2-5sqrt2=$

$\sqrt{2}$ $sqrt 2$

How do you simplify √72−√50sqrt72-sqrt50?