How do you simplify $\frac{\sqrt{63}}{\sqrt{7}}$ $sqrt63/sqrt7$ ?

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Answer 1 · 2016-04-26T00:24:41

$\frac{\sqrt{63}}{\sqrt{7}} = 3$ $sqrt(63)/sqrt(7) = 3$

Using the property that $\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}$ $sqrt(a)/sqrt(b) = sqrt(a/b)$ for $a \geq 0$ $a>=0$ , $b > 0$ $b>0$ :

$\frac{\sqrt{63}}{\sqrt{7}} = \sqrt{\frac{63}{7}} = \sqrt{9} = \sqrt{3^{2}} = 3$ $sqrt(63)/sqrt(7) = sqrt(63/7) = sqrt(9) = sqrt(3^2) = 3$

How do you simplify √63√7sqrt63/sqrt7?