How do you simplify $\sqrt{6} (\sqrt{3} + 5 \sqrt{2})$ $sqrt6 (sqrt3 + 5 sqrt2)$ ?

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How do you simplify $\sqrt{6} (\sqrt{3} + 5 \sqrt{2})$ $sqrt6 (sqrt3 + 5 sqrt2)$ ?

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Answer 1 · 2018-03-21T03:16:05

$10 \sqrt{3} + 3 \sqrt{2}$ $10sqrt3+3sqrt2$
You must distribute the $\sqrt{6}$ $sqrt6$

Explanation:

Radicals can be multiplied, no matter the value under the sign.
Multiply $\sqrt{6} \cdot \sqrt{3}$ $sqrt6*sqrt3$ , which equals $\sqrt{18}$ $sqrt18$ .
$\sqrt{18}$ $sqrt18$ $\to$ $->$ $(\sqrt{9 \cdot 2})$ $(sqrt(9*2))$ $\to$ $->$ $3 \sqrt{2}$ $3sqrt2$ ( $\sqrt{9} = 3$ $sqrt9=3$ )
$\sqrt{6} \cdot 5 \sqrt{2} = 5 \sqrt{12}$ $sqrt6*5sqrt2=5sqrt12$ $\to$ $->$ $5 \cdot \sqrt{3 \cdot 4}$ $5*sqrt(3*4)$
$\sqrt{4} = 2$ $sqrt4=2$ $\to$ $->$ $5 \cdot 2 \sqrt{3} = 10 \sqrt{3}$ $5*2sqrt3=10sqrt3$
Hence, $10 \sqrt{3} + 3 \sqrt{2}$ $10sqrt3 + 3sqrt2$

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How do you simplify $\sqrt{6} (\sqrt{3} + 5 \sqrt{2})$ $sqrt6 (sqrt3 + 5 sqrt2)$ ?

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