How do you simplify $- \sqrt{6} (2 \sqrt{6} - 4 \sqrt{2})$ $-sqrt6(2sqrt6-4sqrt2)$ ?

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Answer 1 · 2018-06-14T18:55:13

$- 12 + 8 \sqrt{3}$ $-12+8sqrt3$

We can distribute the $- \sqrt{6}$ $-sqrt6$ to both terms on the parenthesis. Doing this, we get

$- 2 \sqrt{6 \cdot 6} + 4 \sqrt{2 \cdot 6}$ $-2sqrt(6*6)+4sqrt(2*6)$

This simplifies to

$- 2 \sqrt{36} + 4 \sqrt{12}$ $-2sqrt36+color(blue)(4sqrt(12))$

Which can be rewritten as

$- 12 + 4 \cdot \sqrt{4 \cdot 3}$ $-12+color(blue)(4*sqrt(4*3))$

$\Rightarrow - 12 + 4 \cdot 2 \sqrt{3}$ $=>-12+color(blue)(4*2sqrt3)$

Which finally simplifies to

$- 12 + 8 \sqrt{3}$ $-12+8sqrt3$

Hope this helps!

Answer 2 · 2018-06-14T18:58:47

expand the bracket

$- 2 \sqrt{36} + 4 \sqrt{12}$ $-2sqrt36+4sqrt12$

$\sqrt{36} = 6$ $sqrt36=6$ and $\sqrt{12} = 2 \sqrt{3}$ $sqrt12=2sqrt3$

$- 12 + 8 \sqrt{3}$ $-12+8sqrt3$

How do you simplify −√6(2√6−4√2)-sqrt6(2sqrt6-4sqrt2)?