How do you simplify #[sqrt50] / (3[sqrt2])#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Daniel L. Sep 5, 2016 The value is #5/3# or #1 2/3# Explanation: #sqrt(50)/(3sqrt(2))=(sqrt(2*25))/(3sqrt(2))=(5sqrt(2))/(3sqrt(2))=5/3=1 2/3# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 822 views around the world You can reuse this answer Creative Commons License