How do you simplify #sqrt5(sqrt3 - sqrt7)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Meave60 Sep 15, 2015 #sqrt15-sqrt35# Explanation: #sqrt5(sqrt3-sqrt7)# Distribute the #sqrt5#. #sqrt5xxsqrt3-sqrt5xxsqrt7# Simplify. #sqrt5sqrt3-sqrt5sqrt7# Simplify. #sqrt15-sqrt35# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1267 views around the world You can reuse this answer Creative Commons License