How do you simplify #sqrt5(5 sqrt3 - 2 sqrt4)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Apr 30, 2016 # = 5 sqrt15 -2 sqrt20# Explanation: #color(blue)(sqrt5) * ( 5 sqrt3 - 2 sqrt4)# # = color(blue)(sqrt5) * ( 5 sqrt3 ) + color(blue)(sqrt5) * ( - 2 sqrt4)# # = 5 * sqrt5 * sqrt3 + color(green)( (-2) * sqrt5 * sqrt4# # = 5 * sqrt15 + color(green)( (-2) * sqrt20# # = 5 sqrt15 -2 sqrt20# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 917 views around the world You can reuse this answer Creative Commons License