How do you simplify $sqrt35divsqrt7$ ?

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Answer 1 · 2018-06-13T07:37:36

$sqrt5$

$sqrt35 divide sqrt7$

In fraction form, you can factor out the square root (This is intuitive if you think about how $sqrtx$ is the same as $x^(1/2)$ )

$sqrt(35/7)$

Then dividing numerator and denominator by 7

$sqrt(5/1)$ = $sqrt5$

Answer 2 · 2018-06-13T07:41:10

$sqrt5$

$"using the "color(blue)"law of exponents"$

$•color(white)(x)sqrta/sqrtbhArrsqrt(a/b)$

$sqrt35/sqrt7=sqrt(35/7)=sqrt5$

How do you simplify sqrt35divsqrt7sqrt35divsqrt7?