How do you simplify $\sqrt{3} (\sqrt{12} + \sqrt{6})$ $sqrt3(sqrt12+sqrt6)$ ?

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Answer 1 · 2016-10-24T15:57:48

$= 6 + 3 \sqrt{2}$ $=6+3sqrt2$

Firstly multiply the brackets.

$\sqrt{3} (\sqrt{12} + \sqrt{6}) = \sqrt{3} \sqrt{12} + \sqrt{3} \sqrt{6}$ $sqrt3(sqrt12+sqrt6)=sqrt3sqrt12+sqrt3sqrt6$

$= \sqrt{36} + \sqrt{18}$ $=sqrt36+sqrt18$

Now simplify the square roots.

$= 6 + \sqrt{9 \times 2} = 6 + \sqrt{9} \sqrt{2}$ $=6+sqrt(9xx2)=6+sqrt9sqrt2$

$= 6 + 3 \sqrt{2}$ $=6+3sqrt2$

How do you simplify √3(√12+√6)sqrt3(sqrt12+sqrt6)?