How do you simplify #sqrt3/(6sqrt7)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Greypo · Stefan V. Aug 19, 2017 #sqrt(21)/42# Explanation: Times both the top and bottom by #sqrt(7)#. This gives you #(sqrt(3) * sqrt(7))/(6 * sqrt(7) * sqrt(7)) = sqrt(21)/42# #21# cannot be divided by any square terms, and so this is as simplified as it can be. Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1181 views around the world You can reuse this answer Creative Commons License