How do you simplify #(sqrt3 + 5)(sqrt3 - 3)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Alan N. Jul 14, 2016 #2(sqrt3 -6)# Explanation: #(sqrt3 +5)(sqrt3-3) = 3 -3sqrt3 + 5sqrt3-15# #= sqrt3(5-3)-12# #=2sqrt3-12# #=2(sqrt3-6)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1151 views around the world You can reuse this answer Creative Commons License