How do you simplify $\sqrt{21} \cdot \sqrt{14}$ $sqrt21*sqrt14$ #?

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Answer 1 · 2018-06-09T16:30:32

$7 \sqrt{6}$ $7sqrt6$

$\sqrt{21} \cdot \sqrt{14}$ $sqrt21*sqrt14$

Use the rule:

$\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}$ $sqrta * sqrtb = sqrt(a*b)$

$\sqrt{21} \cdot \sqrt{14} = \sqrt{21 \cdot 14} = \sqrt{294} = \sqrt{7 \cdot 7 \cdot 6}$ $sqrt21*sqrt14 = sqrt(21*14)=sqrt294=sqrt(7*7*6)$

$= \sqrt{7^{2} \cdot 6} = 7 \sqrt{6}$ $=sqrt(7^2*6)=7sqrt6$

How do you simplify √21⋅√14sqrt21*sqrt14#?