How do you simplify $\sqrt{2} (\sqrt{8} + \sqrt{4})$ $sqrt2 (sqrt8 + sqrt4)$ ?

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Answer 1 · 2016-09-25T11:13:14

multiply and try to get rid of $\sqrt{}$ $sqrt()$ 's if possible

$\sqrt{2} (\sqrt{8} + \sqrt{4}) = \sqrt{2} \sqrt{8} + \sqrt{2} \sqrt{4}$ $sqrt(2)(sqrt(8) + sqrt(4)) = sqrt(2)sqrt(8) + sqrt(2)sqrt(4)$

$= \sqrt{16} + \sqrt{2} \cdot 2$ $=sqrt(16) + sqrt(2)*2$

$= 4 + 2 \sqrt{2}$ $= 4+2sqrt(2)$
or
$= 4 + \sqrt{8}$ $= 4+sqrt(8)$

How do you simplify √2(√8+√4)sqrt2 (sqrt8 + sqrt4)?