How do you simplify #sqrt2 ( sqrt8 + 3)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Jun 13, 2015 # color(blue)(4 + 3sqrt2)# Explanation: #color(red)(sqrt2) ( sqrt8 + 3)# Here, we multiply #sqrt2# with each of the terms within the bracket. # = (color(red)(sqrt2). sqrt8) + (color(red)(sqrt2) . 3)# # = color(red)(sqrt16) + 3sqrt2# # = color(blue)(4 + 3sqrt2)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1362 views around the world You can reuse this answer Creative Commons License