How do you simplify #sqrt2(3sqrt2-sqrt2)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Apr 21, 2016 #=4# Explanation: #color(blue)(sqrt2) ( 3 sqrt2 - sqrt2)# # = color(blue)(sqrt2) * ( 3 sqrt2) + color(blue)(sqrt2)* (- sqrt2)# # = 3 * sqrt2 * sqrt2 - (sqrt2 * sqrt2)# # = (3 * 2) - (2 )# # = 6 - 2# #=4# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1029 views around the world You can reuse this answer Creative Commons License