How do you simplify $\sqrt{14} \sqrt{35}$ $sqrt14sqrt35$ ?

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Answer 1 · 2018-05-26T19:05:00

7 $\sqrt{10}$ $sqrt10$

$\sqrt{14} = \sqrt{7 \cdot 2}$ $sqrt14 = sqrt(7*2)$

$\sqrt{35} = \sqrt{5 \cdot 7}$ $sqrt35 =sqrt(5*7)$

Hence,

$\sqrt{14} \cdot \sqrt{35} = \sqrt{7} \cdot \sqrt{2} \cdot \sqrt{5} \cdot \sqrt{7}$ $sqrt14*sqrt35=sqrt7*sqrt2*sqrt5*sqrt7$

Simplify,

$\sqrt{14} \cdot \sqrt{35} = 7 \sqrt{10}$ $sqrt14*sqrt35=7sqrt10$

How do you simplify sqrt14sqrt35√14√35sqrt14sqrt35?