How do you simplify #(sqrt11-3)(sqrt11+3)#?

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Answer 1 · 2018-04-16T22:51:14

The result is #2#.

Use the FOIL method to expand the parentheses:

#color(white)=(sqrt11-3)(sqrt11+3)#

#=sqrt11*sqrt11+3sqrt11-3sqrt11-3*3#

#=sqrt11*sqrt11color(red)cancelcolor(black)(color(black)+3sqrt11-3sqrt11)-3*3#

#=sqrt11*sqrt11-3*3#

#=sqrt11*sqrt11-9#

#=(sqrt11)^2-9#

#=11-9#

#=2#

You can check this using a calculator:

Hope this helped!