How do you simplify #sqrt10xxsqrt8#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Tony B Apr 10, 2018 #4sqrt(5)# Explanation: Given: #sqrt(10)xxsqrt(8)# #sqrt(2xx5)xxsqrt(2xx2^2)# #sqrt(2xx5xx2xx2^2)# #sqrt(2^2xx5xx2^2)# #2xx2xxsqrt(5)# #4sqrt(5)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1037 views around the world You can reuse this answer Creative Commons License