How do you simplify ${(\sqrt{10} - 9)}^{2}$ $(sqrt10 - 9) ^2$ ?

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How do you simplify ${(\sqrt{10} - 9)}^{2}$ $(sqrt10 - 9) ^2$ ?

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Answer 1 · 2016-05-21T01:41:12

We are going to use the identity

${(A - B)}^{2} = A^{2} - 2 \cdot A \cdot B + B^{2}$ $(A-B)^2=A^2-2*A*B+B^2$

Hence we have that

${(\sqrt{10} - 9)}^{2} = {(\sqrt{10})}^{2} - 2 \cdot \sqrt{10} \cdot 9 + 9^{2} = 10 - 18 \cdot \sqrt{10} + 81 = 91 - 18 \cdot \sqrt{10}$ $(sqrt10-9)^2=(sqrt10)^2-2*sqrt10*9+9^2= 10-18*sqrt10+81=91-18*sqrt10$

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How do you simplify ${(\sqrt{10} - 9)}^{2}$ $(sqrt10 - 9) ^2$ ?

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