How do you simplify # sqrt(x^8)/sqrt(x^4)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Sajeev Y. · Stefan V. Apr 10, 2017 The answer should be #x^2# Explanation: #x^(8*1/2)/x^(4*1/2) # #x^4/x^2# #x^(4-2)# using #a^b/a^c=a^(b-c)# #x^2# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1404 views around the world You can reuse this answer Creative Commons License