How do you simplify #sqrt((9x^3y)/(16x^2y^2))#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Kalyanam S. Jul 13, 2018 #color(violet)(=> (3/4) sqrt(x/y)# Explanation: #sqrt((9x^3y)/(16x^2y^2))# #=> sqrt((9 cancel(x^3)^ color(red)x cancel y) / (16 cancel(x^2) cancel(y^2)^color(red)y))# #=> sqrt ((3^2 x)/(4^2y))# #color(violet)(=> (3/4) sqrt(x/y)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1117 views around the world You can reuse this answer Creative Commons License