How do you simplify #sqrt(9x^2) /sqrt( 18y^2)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Ch Mar 22, 2016 #x/(sqrt(2)y)# Explanation: #sqrt(9x^2)/sqrt(18y^2)# #sqrt9=3# #sqrt(x^2)=x# #sqrt18=sqrt(9xx2)=3sqrt2# #sqrt(y^2)=y# Therefore #sqrt(9x^2)/sqrt(18y^2)=(3x)/(3sqrt(2) y)#=#x/(sqrt(2)y)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 3659 views around the world You can reuse this answer Creative Commons License