How do you simplify $\sqrt{8 x^{5}} \cdot \sqrt{3 x}$ $sqrt(8x^5) * sqrt(3x)$ ?

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How do you simplify $\sqrt{8 x^{5}} \cdot \sqrt{3 x}$ $sqrt(8x^5) * sqrt(3x)$ ?

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Answer 1 · 2015-04-07T13:35:33

First you try to get the squares out of the root.

I'll do it step by step:

$\sqrt{8 x^{5}} \cdot \sqrt{3 x} = \sqrt{2^{2} \cdot 2 \cdot {(x^{2})}^{2} \cdot x} \cdot \sqrt{3 x} =$ $sqrt(8x^5)*sqrt(3x)=sqrt(2^2*2*(x^2)^2*x)*sqrt(3x)=$

$2 x^{2} \sqrt{2 x} \cdot \sqrt{3 x} = 2 x^{2} \sqrt{2 x \cdot 3 x} = 2 x^{2} \sqrt{6 \cdot x^{2}} =$ $2x^2sqrt(2x)*sqrt(3x)=2x^2sqrt(2x*3x)=2x^2sqrt(6*x^2)=$

$2 x^{2} \cdot x \cdot \sqrt{6} = 2 x^{3} \sqrt{6}$ $2x^2*x*sqrt6=2x^3sqrt6$

OR :

$\sqrt{8 x^{5}} \cdot \sqrt{3 x} = \sqrt{8 x^{5} \cdot 3 x} =$ $sqrt(8x^5)*sqrt(3x)=sqrt(8x^5*3x)=$

$\sqrt{24 x^{6}} = \sqrt{2^{2} \cdot 6 \cdot {(x^{3})}^{2}} = 2 x^{3} \sqrt{6}$ $sqrt(24x^6)=sqrt(2^2*6*(x^3)^2)=2x^3sqrt6$

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How do you simplify $\sqrt{8 x^{5}} \cdot \sqrt{3 x}$ $sqrt(8x^5) * sqrt(3x)$ ?

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How do you simplify sqrt(8x^5) * sqrt(3x)√8x5⋅√3xsqrt(8x^5) * sqrt(3x)?

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How do you simplify $\sqrt{8 x^{5}} \cdot \sqrt{3 x}$ $sqrt(8x^5) * sqrt(3x)$ ?