How do you simplify $\frac{\sqrt{8}}{\sqrt{3}}$ $sqrt(8) / sqrt(3)$ ?

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Answer 1 · 2016-09-09T18:28:14

$\frac{2 \sqrt{6}}{3}$ $(2 sqrt(6)) / (3)$

We have: $\frac{\sqrt{8}}{\sqrt{3}}$ $(sqrt(8)) / (sqrt(3))$

Let's express the numerator as a product:

$= \frac{\sqrt{4} \cdot \sqrt{2}}{\sqrt{3}}$ $= (sqrt(4) cdot sqrt(2)) / (sqrt(3))$

$= \frac{2 \sqrt{2}}{\sqrt{3}}$ $= (2 sqrt(2)) / (sqrt(3))$

Then, let's rationalise the denominator:

$= \frac{2 \sqrt{2}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}$ $= (2 sqrt(2)) / (sqrt(3)) cdot (sqrt(3)) / (sqrt(3))$

$= \frac{2 \cdot \sqrt{6}}{3}$ $= (2 cdot sqrt(6)) / (3)$

$= \frac{2 \sqrt{6}}{3}$ $= (2 sqrt(6)) / (3)$

How do you simplify √8√3sqrt(8) / sqrt(3)?