How do you simplify #sqrt(68ac^3)/sqrt(27a^2)#?

1 Answer
Nathaniel Reed
Sep 21, 2017

#(2csqrt(51ac))/(9a)#

Explanation:

#(sqrt(68ac^3))/(sqrt(27a^2))# can simplify to #(2csqrt(17ac))/(3asqrt(3))#
Then, you multiply fraction by 1 to not change the value of the expression.
You multiply by #sqrt(3)/sqrt(3)# which is equal to 1.
This is because you need to get rid of the root in the denominator. #sqrt(3)*sqrt(3)=3#

#(2csqrt(17ac))/(3asqrt(3))*(sqrt(3)/sqrt(3))=(2csqrt(51ac))/(3asqrt(9))=(2csqrt(51ac))/(9a)#

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