How do you simplify #sqrt(5) / sqrt(8)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Tony B May 13, 2016 #sqrt(10)/4# Explanation: Given:#" "sqrt(5)/sqrt(8)# Multiply by 1 but in the form of #1=sqrt(8)/sqrt(8)# #" "=sqrt(5)/sqrt(8)xxsqrt(8)/sqrt(8)# #" "=(sqrt(5)sqrt(8))/8# But #8# is the same as #2^2xx2" so "sqrt(8)=2sqrt(2)# #" "=(2sqrt(5)sqrt(2))/8 " "=" "sqrt(5xx2)/4# #" "=sqrt(10)/4# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 2921 views around the world You can reuse this answer Creative Commons License