How do you simplify #(sqrt 5 + 9 sqrt2)(4 sqrt5 - sqrt 2)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer ali ergin May 29, 2016 #(sqrt5+9sqrt2)(4sqrt5-sqrt2)=2+35sqrt10# Explanation: #(sqrt5+9sqrt2)(4sqrt5-sqrt2)# #=4sqrt5*sqrt5-sqrt5*sqrt2+9sqrt2*4sqrt5-9sqrt2*sqrt2# #=4(sqrt5)^2-sqrt10+36sqrt10-9(sqrt2)^2# #=4*5+35sqrt10-9*2# #=20+35sqrt10-18# #=2+35sqrt10# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1440 views around the world You can reuse this answer Creative Commons License