How do you simplify # sqrt (45x^2)/ sqrt 9#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer HF May 25, 2016 #xsqrt5# Explanation: #sqrt(45x^2)/(sqrt9) = (sqrt9 xx sqrt5 xx sqrt(x^2))/(sqrt9)# cancel #sqrt9# and #sqrt(x^2) = x# answer after cancelling #sqrt9# is #xsqrt5# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1182 views around the world You can reuse this answer Creative Commons License