How do you simplify #sqrt(3v)(sqrt6+sqrt10)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Tazwar Sikder May 18, 2017 #3 sqrt(2 v) + sqrt(30 v)# Explanation: We have: #sqrt(3 v) (sqrt(6) + sqrt(10))# Let's expand the parentheses: #= sqrt(3 v) cdot sqrt(6) + sqrt(3 v) cdot sqrt(10)# #= sqrt(3 v cdot 6) + sqrt(3 v cdot 10)# #= sqrt(18 v) + sqrt(30 v)# #= 3 sqrt(2 v) + sqrt(30 v)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 950 views around the world You can reuse this answer Creative Commons License