How do you simplify $sqrt(32xy^2) div sqrt4$ ?

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Answer 1 · 2018-03-11T11:56:30

$ysqrt(8x)$

$sqrt(32xy^2)-:sqrt4$
$=(sqrt32xxsqrtx xxsqrt(y^2))-:sqrt4$
$=(cancel(sqrt4)xxsqrt8xxsqrtx xxy)-:cancel(sqrt4$
$=yxxsqrt8xxsqrtx$
$=ysqrt(8x)$

How do you simplify sqrt(32xy^2) div sqrt4sqrt(32xy^2) div sqrt4?