How do you simplify $\sqrt{\frac{32}{t^{4}}}$ $sqrt(32/t^4)$ ?

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How do you simplify $\sqrt{\frac{32}{t^{4}}}$ $sqrt(32/t^4)$ ?

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Answer 1 · 2017-04-03T20:41:23

$4 \sqrt{2} t^{- 2}$ $4sqrt(2)t^(-2)$

Explanation:

$\sqrt{\frac{32}{t^{4}}} = \frac{\sqrt{32}}{\sqrt{t^{4}}} = \frac{\sqrt{(16) (2)}}{t^{2}} = \frac{\sqrt{16} \sqrt{2}}{t^{2}} = \frac{4 \sqrt{2}}{t^{2}} = 4 \sqrt{2} t^{- 2}$ $sqrt(32/t^4)=sqrt(32)/sqrt(t^4)=sqrt((16)(2))/t^2=(sqrt(16)sqrt(2))/t^2=(4sqrt(2))/t^2=4sqrt(2)t^(-2)$

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How do you simplify $\sqrt{\frac{32}{t^{4}}}$ $sqrt(32/t^4)$ ?

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How do you simplify $\sqrt{\frac{32}{t^{4}}}$ $sqrt(32/t^4)$ ?