How do you simplify sqrt(3/16)*sqrt(9/5)√316⋅√95?
2 Answers
Explanation:
Note that if
sqrt(ab) = sqrt(a)sqrt(b)√ab=√a√b
If
sqrt(a/b) = sqrt(a)/sqrt(b)√ab=√a√b
If
sqrt(a^2) = a√a2=a
When simplifying square roots of rational expressions, I like to make the denominator square before splitting the square root. That way we don't have to rationalise the denominator later...
sqrt(3/16)*sqrt(9/5) = sqrt(3/16)*sqrt((9*5)/(5*5))√316⋅√95=√316⋅√9⋅55⋅5
color(white)(sqrt(3/16)*sqrt(9/5)) = sqrt(3/4^2)*sqrt(45/5^2)√316⋅√95=√342⋅√4552
color(white)(sqrt(3/16)*sqrt(9/5)) = sqrt((3*45)/(4^2*5^2))√316⋅√95=√3⋅4542⋅52
color(white)(sqrt(3/16)*sqrt(9/5)) = sqrt(3*45)/sqrt(4^2*5^2)√316⋅√95=√3⋅45√42⋅52
color(white)(sqrt(3/16)*sqrt(9/5)) = sqrt(3*3^2*5)/sqrt((4*5)^2)√316⋅√95=√3⋅32⋅5√(4⋅5)2
color(white)(sqrt(3/16)*sqrt(9/5)) = (sqrt(3^2)*sqrt(15))/sqrt(20^2)√316⋅√95=√32⋅√15√202
color(white)(sqrt(3/16)*sqrt(9/5)) = (3sqrt(15))/20√316⋅√95=3√1520