How do you simplify #sqrt( 3/10) *sqrt(5/8)#?

2 Answers
A08
Jan 24, 2016

#sqrt 3/4#
or #0.433#

Explanation:

#sqrt (3/10).sqrt (5/8)#

Since both fractions are square roots, therefore, taking both fractions under the same root sign

#sqrt (3/10. 5/8)#
or simplifying we obtain #sqrt (3/cancel10_2. cancel5^1/8)#
#=sqrt (3/2. 1/8)#
Multiplying the numerators and denominators respectively
#=sqrt (3/16)#
Now we know that #sqrt 16=4#, we obtain
#=sqrt 3/4#
Inserting the value of #sqrt 3=1.732# in the numerator and dividing with the denominator, we obtain

Jim G.
Jan 24, 2016

# 1/4 sqrt3 #

Explanation:

Using the following :

# • sqrta xx sqrtb = sqrtab hArr sqrtab = sqrta xx sqrtb #

# sqrt( 3/10). sqrt(5/8) = sqrt(3/10 xx 5/8) = sqrt(15/80 #

# = sqrt(3/16) = sqrt3/sqrt16 = sqrt3/4 =1/4 sqrt3 #

Related questions
See all questions in Multiplication and Division of Radicals
Impact of this question
1301 views around the world
You can reuse this answer
Creative Commons License