How do you simplify #sqrt(2u^3 w^2)*sqrt(10u^6 w^4)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Bill Jorgensen Jun 7, 2018 #2u^4w^3sqrt(5u)# Explanation: #=sqrt(2u^3 w^2)*sqrt(10u^6 w^4)# #=sqrt(2u^3 w^2*10u^6 w^4)# #=sqrt(20u^9 w^6)# #=2u^4w^3sqrt(5u)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1500 views around the world You can reuse this answer Creative Commons License