How do you simplify #sqrt(27y)/sqrt(3y)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Mar 8, 2016 #=color(green)(3 # Explanation: #sqrt27# Simplifying #sqrt27= sqrt (3 *3 *3 )= color(green)(3 sqrt3# #(sqrt(27y))/(sqrt(3y)# #=color(green)((3 sqrt(3y)))/(sqrt(3y)# #=color(green)((3 cancelsqrt(3y)))/(sqrtcancel(3y)# #=color(green)(3 # Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1137 views around the world You can reuse this answer Creative Commons License