How do you simplify #sqrt(24 x^6)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Lovecraft Sep 18, 2015 #sqrt(24x^6) = 2|x^3|sqrt(6)# Explanation: #sqrt(24x^6) = sqrt(4*6*x^6) = 2sqrt(6x^6) = 2sqrt(6x^2*x^2*x^2) = 2|x^3|sqrt(6)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1557 views around the world You can reuse this answer Creative Commons License