How do you simplify #sqrt(220x^3)/sqrt(5x)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Jul 21, 2015 #=(2sqrt55x)/sqrt5# Explanation: #sqrt(220x^3)/(sqrt(5x# #sqrt(220) = sqrt(2*2*11*5)# #=sqrt(2^2*11*5)# #=2sqrt55# The expression can be re written as: #sqrt(220x^3)/(sqrt(5x# #=# #(2sqrt55 * x^(3/2))/(sqrt5*x^(1/2)# #=(2sqrt55 *x^color(blue)((3/2-1/2)))/sqrt5# #=(2sqrt55x)/sqrt5# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1459 views around the world You can reuse this answer Creative Commons License