How do you simplify $\frac{\sqrt{2}}{\sqrt{8}}$ $sqrt(2) / sqrt(8)$ ?

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How do you simplify $\frac{\sqrt{2}}{\sqrt{8}}$ $sqrt(2) / sqrt(8)$ ?

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Answer 1 · 2016-05-02T09:02:34

$\frac{\sqrt{2}}{\sqrt{8}} = \frac{1}{2}$ $sqrt(2)/sqrt(8)=1/2$

Explanation:

Using the property that $\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}$ $sqrt(a)/sqrt(b) = sqrt(a/b)$ for $b > 0$ $b > 0$ we have

$\frac{\sqrt{2}}{\sqrt{8}} = \sqrt{\frac{2}{8}} = \sqrt{\frac{1}{4}} = \frac{\sqrt{1}}{\sqrt{4}} = \frac{1}{2}$ $sqrt(2)/sqrt(8) = sqrt(2/8) = sqrt(1/4) = sqrt(1)/sqrt(4) = 1/2$

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How do you simplify $\frac{\sqrt{2}}{\sqrt{8}}$ $sqrt(2) / sqrt(8)$ ?

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How do you simplify sqrt(2) / sqrt(8)√2√8sqrt(2) / sqrt(8)?

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How do you simplify $\frac{\sqrt{2}}{\sqrt{8}}$ $sqrt(2) / sqrt(8)$ ?