How do you simplify (sqrt(2)*sqrt(5))(√2⋅√5)? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer VNVDVI Mar 25, 2018 sqrt(10)√10 Explanation: Recall that sqrt(a)*sqrt(b)=sqrt(a*b)√a⋅√b=√a⋅b Thus, sqrt(2)*sqrt(5)=sqrt(2*5)=sqrt(10)√2⋅√5=√2⋅5=√10 Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}2√3? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)73√5? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))(√a+√b)(√a−√b)? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}2x√5x? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)√5√15? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))(7√13+2√6)(2√3+3√6)? See all questions in Multiplication and Division of Radicals Impact of this question 11911 views around the world You can reuse this answer Creative Commons License