How do you simplify $\sqrt{\frac{2}{3}} + \sqrt{\frac{3}{2}}$ $sqrt(2/3)+sqrt(3/2)$ ?

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How do you simplify $\sqrt{\frac{2}{3}} + \sqrt{\frac{3}{2}}$ $sqrt(2/3)+sqrt(3/2)$ ?

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Answer 1 · 2016-03-30T23:06:16

$\frac{5 \sqrt{6}}{6}$ $(5sqrt(6))/6$

Explanation:

From the given expression $\sqrt{\frac{2}{3}} + \sqrt{\frac{3}{2}}$ $sqrt(2/3)+sqrt(3/2)$

$\sqrt{\frac{2}{3}} + \sqrt{\frac{3}{2}}$ $sqrt(2/3)+sqrt(3/2)$

$\sqrt{\frac{2}{3} \cdot \frac{3}{3}} + \sqrt{\frac{3}{2} \cdot \frac{2}{2}}$ $sqrt(2/3*3/3)+sqrt(3/2*2/2)$

$\sqrt{\frac{6}{9}} + \sqrt{\frac{6}{4}}$ $sqrt(6/9)+sqrt(6/4)$

$\frac{\sqrt{6}}{3} \cdot \frac{2}{2} + \frac{\sqrt{6}}{2} \cdot \frac{3}{3}$ $sqrt(6)/3*2/2+sqrt(6)/2*3/3$

$\frac{2 \sqrt{6}}{6} + \frac{3 \cdot \sqrt{6}}{6}$ $(2sqrt(6))/6+(3*sqrt(6))/6$

$\frac{5 \sqrt{6}}{6}$ $(5sqrt(6))/6$

For what I know , radicals are already on its simplest form when there is no radical at the denominator, there is no fraction in the radicand, and the radicand is not reducible anymore.

God bless...I hope the explanation is useful.

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How do you simplify $\sqrt{\frac{2}{3}} + \sqrt{\frac{3}{2}}$ $sqrt(2/3)+sqrt(3/2)$ ?

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How do you simplify $\sqrt{\frac{2}{3}} + \sqrt{\frac{3}{2}}$ $sqrt(2/3)+sqrt(3/2)$ ?