How do you simplify #sqrt(162x^9 y^3) ÷ sqrt(2xy)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Phillip E. · Konstantinos Michailidis Jul 22, 2016 Do the division and then take the square root. Explanation: #sqrt(162x^9y^3) divide sqrt(2xy)=sqrt((162x^9y^3)/(2xy))=sqrt(81x^8y^2)=9x^4*absy# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1028 views around the world You can reuse this answer Creative Commons License