How do you simplify $\sqrt{162 x^{9} y^{3}} \div \sqrt{2 x y}$ $sqrt(162x^9 y^3) ÷ sqrt(2xy)$ ?

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How do you simplify $\sqrt{162 x^{9} y^{3}} \div \sqrt{2 x y}$ $sqrt(162x^9 y^3) ÷ sqrt(2xy)$ ?

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Answer 1 · 2016-07-22T22:04:02

Do the division and then take the square root.

Explanation:

$\sqrt{162 x^{9} y^{3}} \div \sqrt{2 x y} = \sqrt{\frac{162 x^{9} y^{3}}{2 x y}} = \sqrt{81 x^{8} y^{2}} = 9 x^{4} \cdot | y |$ $sqrt(162x^9y^3) divide sqrt(2xy)=sqrt((162x^9y^3)/(2xy))=sqrt(81x^8y^2)=9x^4*absy$

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How do you simplify $\sqrt{162 x^{9} y^{3}} \div \sqrt{2 x y}$ $sqrt(162x^9 y^3) ÷ sqrt(2xy)$ ?

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Explanation:

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How do you simplify √162x9y3÷√2xysqrt(162x^9 y^3) ÷ sqrt(2xy)?

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How do you simplify $\sqrt{162 x^{9} y^{3}} \div \sqrt{2 x y}$ $sqrt(162x^9 y^3) ÷ sqrt(2xy)$ ?