How do you simplify $\sqrt{15 x} \times \sqrt{21 x}$ $sqrt(15x) times sqrt(21x)$ ?

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Answer 1 · 2016-07-11T15:39:25

$3 x \sqrt{35}$ $3xsqrt(35)$

Notice that 3 is a factor of both 15 and 21 and so is $x$ $x$

$\sqrt{3 \times 5 \times x} \times \sqrt{3 \times 7 \times x}$ $sqrt(3xx5xx x)xxsqrt(3xx7xx x)$

$\sqrt{3 x} \times \sqrt{5} \times \sqrt{3 x} \times \sqrt{7}$ $sqrt(3x)xxsqrt(5)xx sqrt(3x)xxsqrt(7)$

But $\sqrt{3 x} \times \sqrt{3 x} = 3 x$ $sqrt(3x)xxsqrt(3x)=3x$

$3 x \sqrt{5} \sqrt{7} = 3 x \sqrt{5 \times 7} = 3 x \sqrt{35}$ $3xsqrt(5)sqrt(7) = 3xsqrt(5xx7)=3xsqrt(35)$

Answer 2 · 2016-07-11T15:40:47

$\sqrt{15 x} \cdot \sqrt{21 x} = 3 x \sqrt{35}$ $sqrt(15x)*sqrt(21x)=3xsqrt(35)$

$\sqrt{15 x} \cdot \sqrt{21 x}$ $sqrt(15x)*sqrt(21x)$

$\sqrt{(15 x) \cdot (21 x)}$ $sqrt((15x)*(21x))$

$\sqrt{(3) (5) x \cdot 3 (7) x}$ $sqrt((3)(5)x*3(7)x)$

$\sqrt{3^{2} \cdot x^{2} \cdot 35}$ $sqrt(3^2*x^2*35)$

$3 x \sqrt{35}$ $3xsqrt(35)$

God bless....I hope the explanation is useful.

How do you simplify √15x×√21xsqrt(15x) times sqrt(21x)?