How do you simplify #sqrt(14x)(3-sqrt(2x))#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Harish Chandra Rajpoot Jul 27, 2018 #3\sqrt{14x}-2x\sqrt{ 7}# Explanation: Given that #\sqrt{14x}(3-\sqrt{2x})# #=3\sqrt{14x}-\sqrt{2x}\sqrt{14x}# #=3\sqrt{14x}-\sqrt{2x\cdot 14x}# #=3\sqrt{14x}-\sqrt{(2x)^2\cdot 7}# #=3\sqrt{14x}-\sqrt{(2x)^2}\sqrt{ 7}# #=3\sqrt{14x}-2x\sqrt{ 7}# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1470 views around the world You can reuse this answer Creative Commons License