How do you simplify # sqrt ((14x)/(18x))#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Tony B Aug 7, 2016 #1/3sqrt7# Explanation: Write as #" "sqrt(14/18xx x/x) = sqrt(14/18)# Write as #" "sqrt((2xx7)/(2xx9)) = sqrt((7/9)# Write as #sqrt(7)/sqrt(9)# But #9=3^2# giving #sqrt(7)/sqrt(3^2)# #=1/3sqrt7# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 843 views around the world You can reuse this answer Creative Commons License