How do you simplify sqrt(120x^4)/sqrt(6x)?

1 Answer
Tony B
Mar 14, 2016

2xsqrt(5x)-= 2sqrt(5x^3)

I would suggest that 2xsqrt(5x) may be the better choice of the two!

Explanation:

Given:" "sqrt(122x^4)/sqrt(6x)

Prime factors of 6 are: 2 and 3

#Prime factors of 120 are:2^2, 2, 3,5

So the given expression can be written as:

sqrt(2^2xx2xx3xx5xx(x^2)^2)/(sqrt(2xx3xxx)

This gives:

2x^2xx(sqrt(2)xxsqrt(3)xxsqrt(5))/(sqrt(2)xxsqrt(3)xxsqrt(x))

2x^2xxsqrt(2)/sqrt(2) xxsqrt(3)/sqrt(3)xxsqrt(5)/sqrt(x)

2x^2xxsqrt(5)/sqrt(x)

Multiply by 1 but in the form of 1=sqrt(x)/sqrt(x)

2x^2xxsqrt(5)/sqrt(x)xxsqrt(x)/sqrt(x)

2x^2xxsqrt(5x)/x

2xsqrt(5x)-= 2sqrt(5x^3)

I would suggest that 2xsqrt(5x) may be the better choice of the two!

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